Actually it’s a Paralympic Maths lesson: teach area and circumference of circles in the context of Paralympic Archery.
Like what you see? More lessons like this are freely available on ActiveTeach – no login required.
The Rugby World Cup is upon us. There’s a lot more mathematics to rugby than you might think, and we’ve created a bespoke Beast Index to prove it.
Keep your class on their toes with these AO1 and AO3 problem-solving questions on averages & range, and using formulae:
So while you’re waiting for the street party to warm up, why not have a go at this fun Level 5/6 algebra activity:
Note: No turtles were harmed in the making of these activities!
Squeezing in before or after your half-term, we thought you might like to have some extra practice material for AQA GCSE Maths 4360 Unit 2.
The Unit 2 exam is on 9 March. Don’t forget this is a non-calculator paper.
Our Longman AQA GCSE Maths series is full of support for the whole specification, with particular focus on the new question types AO2 and AO3.
And here are the Unit 2 Practice Paper answers – enjoy!
We just found out something new….
It turns out that if you take the first ten terms of any Fibonacci sequence, the sum of those 10 terms is equal to the 7th term multiplied by 11. Got it?
OK, let’s unpack that. Here’s the most basic Fibonacci sequence:
If you plug these into your head/calculator, you will find that the sum of these 10 terms is 143.
Much quicker: take the 7th term (in this case 13), multiply that by 11 and you get, as if by magic… 143.
And it works for any Fibonacci sequence. Let’s imagine one with bigger numbers starting with (to pick a number completely at random) 42:
42, 42, 84, 126, 210, 336, 546, 882, 1428, 2310
So we add all the terms up on a calculator and get 6,006.
Now, much quicker, jot down the 7th term (here: 546), multiply it by 11 and, hey presto: 546×11=6,006
It’s a trick you can cheerfully teach to your maths students – get them to take it home and impress their parents. Something along the lines: “hey, dad/mum, I bet I can add up a Fibonacci sequence faster in my head than you can using a calculator”.
One final note: the covers on our (as in: Longman’s) AQA GCSE Maths Student Books this year were inspired by spirals. A spiral galaxy on our Foundation sets book, a spiral staircase on our Higher sets book, and a chameleon’s tail on our Middle sets book (someone must’ve been wondering what this image was?) –
Jonathon Cox at The Littlehampton Academy
for successfully working out where Holmes and Watson must go next.
And the answer is:
Coming up next… a spot of Christmas shopping in Episode 5 on Wednesday.
Here is the winning solution to episode 4:
The solution to how far away Moriarty is from the tunnel.
The path of the firework is y=300+44x-x^2. This is a quadratic so using the quadratic formula to find x when y=0
x= (-b +/- square root (b^2 – 4ac))/(2a)
where a=-1, b=44 and c=300
x = (-44 +/- square root (44^2 – 4X-1X300))/(2X-1)
x = (-44 +/- square root (1936 + 1200))/(-2)
x = (-44 +/- square root (3136))/(-2)
x = (-44 +/- 56)/(-2)
Either x = (-44 – 56)/(-2) = -100/-2 = +50 (where the tunnel is)
or x = (-44 + 56)/(-2) = 12/-2 = -6 (where Moriarty must have fired the firework from)
So 50 – -6 = 56 metres away from the tunnel
Moriarty is 56 metres away
Using the Coordinates of the Tate Modern (34, 14) and the code FG DG.
Using a shifted substitution D=1, E=2, F=3 etc
The Coordinates generated from substitution of CK EE gives (08, 22) which give the coordinates for Oxford Circus
Moriarty’s Target is Oxford Circus
SHERLOCK HOLMES AND THE MYSTERY OF THE DEVIL’S EYE
Episode 4 – “G U N P O W D E R , T R E A S O N A N D P L O T”
The story so far… Called to investigate the disappearance from Harrods of the world’s largest ruby, the Devil’s Eye, Holmes and Watson follow a trail from there to the London Eye. Further clues at the London Eye lead them into a Halloween, midnight chase through the tunnels under the Thames. Ably assisted by two Maths teachers from Gloucestershire College, they solve the probability clues and arrive at… B O R O U G H M A R K E T!
Emerging from the tunnels, Holmes and Watson finally catch a glimpse of the thief in EPISODE 4:
And here’s the accompanying worksheet:
WHAT TO DO:
DOWNLOAD THE PDFs, SOLVE THE CLUES, AND SUBMIT YOUR ANSWERS TO: SherlockH_221B@yahoo.co.uk
BY MONDAY 15th NOVEMBER.
The winning entry will be drawn at random from all correct answers, and will receive a FREE Class set of Longman’s unique AQA A-A* and G-F Practice Books (15 copies of each) and a tin of Cadbury’s Heroes.
If you’re NEW to this competition…
View this page of our blog to keep up to date with all the action. The competition is free to enter, and you can join in any Round/Episode. All the page references in the Episode point to maths support in our AQA GCSE Middle sets Student Book. All new and existing subscribers are entitled to receive a single free copy of this book – request your copy by leaving a comment on this post.
GOT ANY QUESTIONS? Just leave a comment on this post and we’ll get straight back to you.